2x+X^2=1260

Solution for 2x+X^2=1260 equation:

2x+x^2=1260

We move all terms to the left:

2x+x^2-(1260)=0

a = 1; b = 2; c = -1260;
Δ = b2-4ac
Δ = 22-4·1·(-1260)
Δ = 5044
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5044}=\sqrt{4*1261}=\sqrt{4}*\sqrt{1261}=2\sqrt{1261}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{1261}}{2*1}=\frac{-2-2\sqrt{1261}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{1261}}{2*1}=\frac{-2+2\sqrt{1261}}{2}
$